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Topic: Better tie break method.
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phystutordotcom wrote:
How about this.
The player who would have won on tie break gets white in the first Playoff game. At move 10 a second playoff game starts colors reversed. A new game start whenever the last game to start reaches move 10. The first non draw to occurr decides who wins the tournament. |
Sorry but I think that's a horrible idea. First, if the initial game is won after fifty moves, which is not at all unusual, an extra five redundant games will have been created. Abandoning those games is unfair to whichever player was winning them; continuing them is a burden on both players. Second, a player who is winning in one game but losing in another has an incentive to delay because the criterion is one of time.
I'd prefer to see a simple tie-break, such as average rating of defeated players plus half the average rating of drawn players, taken over all rounds of the tournament. In the unlikely event of that being tied, just declare joint winners.
Dave.
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How about a virtual duel ... fitting with the medieval feel of chess. Each player in turn places his queen somewhere on an empty board (White first). Once that is done (the first shots!), a legal randomly generated end-game is created around those pieces. The board is revealed whereupon the players see whether either of the first shots were fatal or if the duel must continue (completion of the end game with White moving first).
Seriously, developing a new tie break method is difficult. The more complex you make it the greater the number of problems that will crop up ... as pointed out about phys' idea. Even richerby's simpler solutions is still basically a random result because the ratings of all the players that started WILL swing considerably by tournament end. As an extreme example, you may have beat a 2200 rated player but by the final round, he has abandoned that account and has a rating of 1400. Easier to flip a coin!
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First method : (without history)
An additional match (1 game) between the 2 first players ...if the match is a draw the payer who played with black will advance !
but who's white and who's black ?
the highest rating player will be white
Second method : (using history)
look to the tournament's history...4 players A/B/C/D
-let's say that A and B end first with 4 wins:
*if A won both his games against B then A will advance.
*if A won 1 game and lost the other one against B...in this situation I sugest the first method to be applied :
An additional match (1 game) between the 2 first players ...if the match is a draw the payer who played with black will advance !
but who's white and who's black ?
the highest rating player will be white |
and it's the fairest possible way to break ties.
waiting your answers,
Salam.
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This is the current method being used here.
Tie-Breaks
When two or more players obtain the same score in the final round of a tournament, the following tie-break methods will be applied in order:
Averaged opponent score: This value is computed by adding the scores obtained by all the opponents in all rounds (ignoring the games played against the player) and dividing the total by the number of games played. The player with the highest value will be the winner, presuming that he/she had a tougher competition.
Rating: The player with the highest rating will be the winner.
Random: A random player will be the winner.
The problem is in order to maximize the number of wins of my opponents one should
1. Advance with the lowest possible score. This means that one would resign his last game regardless of position If he wins his first 5.
2. Try to tie for first in the first 2 rounds.
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too complicated and unfair !
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